# Line slope calculator 3x-7y=-32

**Straight line given by points A[1; 5] and B[8; 8]**

## Calculation:

**Slope-intercept form of line:**y = 0.4286x+4.5714

**Canonical form of the line equation:**3x-7y+32 = 0

**Parametric form of the line equation:**

x = 7t+1

y = 3t+5 ; t ∈ R

**Slope:**m = 0.4286

**Slope angle of line: φ =**23°11'55″ = 0.4049 rad

**X intercept:**x

_{0}= -10.6667

**Y intercept:**y

_{0}= q = 4.5714

**Distance line from the origin:**d

_{0}= 4.2018

**The length of the segment AB: |AB| =**7.6158

**Vector: AB =**(7; 3)

**Normal vector: n =**(3; -7)

**Midpoint of the segment AB: M =**[4.5; 6.5]

**Perpendicular Bisector equation:**7x+3y-51 = 0

**Vector OA = (1; 5) ; |OA| = 5.099**

**Vector OB = (8; 8) ; |OB| = 11.3137**

**Scalar product OA .OB = 48**

**Angle ∠ AOB = 33°41'24″ = 0.588 rad**